Question

Complete the shear moment diagram

15 kN 3 kN/m A B С -4.5 m +-1.5 m-+-1.5 m-4

Answer 1

SOLUTION 15KM ब 4.5m ISK A c •Sm 1.5m Mb=0 15x115=ReX3 TRC = 7.56N] Ret RC = 15kn | BB 27.5kn *** TRO 6.75kA 3lnym 05m $7.5kN TRA 77.5kN; RA = 6s+75kA = 125 kv MA = 6.7583 + 7.5x4.5 =54 KNim BkN/m 15kW Sukn.m c TiSm TM Paskn 4.5m 14.25kw 14.25 KN ître vove VA = 14.25kw Ve z VA + (rece of louded diodsum = 14:25- (**45*3) b/w A&B) 7.5kN 8.1.5m C 19.5kn 4.5m VB = 7.25 kN 1.5m

ve' = VB +point load) versanta 57,5-15 5-7.5kw Ve=Vc ==75kn 11:25knim B.M.D 4.5m R Bl B A ok 15m MA==Suknum nave 115m atve My = MA+ (aseu of Sohd Bl 448) Sykum = -64 tf(W25=25]4:5)*67.53 = -54+ [54] [84] 0 é gre!) Me'= MB + (Area of SofD blw MB=0 kn.m = 0 + (7.5X1.5) me' = 11.25 kv.m ist Me = met (Asea of S.FD bho bec) (7.5X1.5) 11.25 Extrakt = 11.25 - 11.25 ME=0 kn.ml