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If cos theta= square root 11/6 and tan theta < 0, find the exact value of sin the

1. If cos os (0) – VII and tan(Q) <o, find the exact value of sino).
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Answer #1

we have oso= u tan(oko 6 In quadeant , 2010 20 and tan oco. se, o wiel is quadiant IV. Now coso = B H P by bythagous theorem,

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