Question

Find the equation of the line that is a perpendicular bisector of AB, with the endpoints A(6, 6) and B(3,-2). Y = X

Answer 1

all a ） First of recall following (1) It line passes through two points say (24,9) and (&2, 9), then the slope of the line y Y₂ (m) = 242 (2) If two If two lines aree perpendicular having slope mi and ma e then (3) If line passes through (2419) and has slope 'm', then it's eqr is y-y m(0-24) -1 mima = a

SOLO Given the line AB with end point A= (676) and B= (3,-2) perpendiulas bisector M A(6,6) B (3-2) Here scope of line AB is 6- (-2) 6-(3) f) = ma Since we 2 know If two lines are perpendicular product of their slope =-1 than So If If m denote the scope of perependiulare bisector , then (using ()) mimo ✓ -1 => S.M. = I C) -3 L 27 28 Since CD is the bisector ( see fig above) So M is is mid point of CD so ME (52) = (*12) ) >

so we get the perpendicular bisector has slope My = -3/4 and passes through (1912) so it's egr is 8-9, 77, (x-x) 24-424 (1-1) => $C 8-2) = -3 (-а) — 16 = -3 ata7 87 —16 - a720 - 2 3. ТЯ 43 го г 31 t%) 3х +84 243 which is the required ear of perpendicular bisector of AB