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(1 point) The function f(x) = 7 (152) is represented as a power series 00 f(x) = 42 10 Find the first few coefficients in th

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7 Given that f (x) = (1–53) 7 (1+$2)2 = 7(1–53) = 7(1-5x) = 7(1+2(5x)+3(5x)* +4(5x)*+5 (5x) ...) = 7[1+10x +75x* +500x +3125x

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