Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 44
Alternative Hypothesis, Ha: μ ≠ 44
The test statistic is single mean z test
Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (45 - 44)/(5/sqrt(50))
z = 1.414
P-value Approach
P-value = 0.157
As P-value >= 0.05, fail to reject null hypothesis.
No, we cannot conclude
A manufacturer claims that the mean lifetime, it, of its light bulbs is 44 months. The...
A manufacturer claims that the mean lifetime, u, of its light bulbs is 52 months. The standard deviation of these lifetimes is 6 months. Fifty bulbs are selected at random, and their mean lifetime is found to be 50 months. Can we conclude, at the 0.05 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 52 months? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at...
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imited A manufacturer claims that the mean lifetime, H, of its light bulbs is 52 months. The standard deviation of these lifetimes is 6 months. Nine bulbs are selected at random, and their mean lifetime is found to be 51 months. Assume that the population is normally distributed. Can we conclude, at the 0.05 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 52 months? Perform a two-tailed test. Then fill in the...
A manufacturer daims that the mean lifetime, H, of its light bulbs is 43 months. The standard deviation of these lifetimes is 8 months. Seventy bulbs are selected at random, and their mean lifetime is found to be 44 months. Can we conclude, at the 0.01 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 43 months? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at...
= Question 10 of 11 (1 point) Question Attempt: 1 of Unlimited Em A manufacturer claims that the mean lifetime, H, of its light bulbs is 52 months. The standard deviation of these lifetimes is 6 months. Nine bulbs are selected at random, and their mean lifetime is found to be 51 months. Assume that the population is normally distributed. Can we conclude, at the 0.05 level of significance, that the mean lifetime of light bulbs made by this manufacturer...
Where it says “the type of test statistic , chose one) the options are Z, t , Chi square , F” thank you! Spg 2019 (2192) Quiz 6: Chapters 8, 11 5 of 8 A manufacturer claims that the lifeti , of its light bulbs is 43 months. The standard deviation of these lifetimes is 4 months. Seventeen bulbs are t random, and their mean lifetime is found to be 42 months. Assume that the population is normalily conclude, at...
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Please answer neatly and correctly! A light bulb manufacturer wants to compare the mean lifetimes of two of its light bulbs, model A and model B. Independent random samples of the two models were taken. Analysis of 15 bulbs of model A showed a mean lifetime of 1350 hours and a standard deviation of 102 hours. Analysis of 14 bulbs of model B showed a mean lifetime of 1384 hours and a standard deviation of 91 hours. Assume that the...