Question

Nick decided to test if there was an association between students class level and their food preference. He took a random sa

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Answer #1

The expected count for (sophomore, Tacos) is computed here as:

E(Sophomore, Tacos) = n(Sophomore) n(Tacos) / n(Total)

= (19 + 25 + 10 + 12)*(18 + 25 + 22 + 16) / 245

= 66*81 / 245

= 21.8204

Therefore 21.8204 is the expected count here.

b) Degrees of freedom here is computed as:
Df = (num of columns - 1)(num of rows - 1) = (4 - 1)(4 - 1) = 9

Therefore the p-value here is computed from chi square distribution tables as:

p = P(\chi^2_9 > 8.176) = 0.5165

Therefore 0.5165 is the required p-value here.

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