Question

DETAILS 2. (-12 points) TIPLER6 24.P.034. For the circuit shown in the figure below, (v -8.6 V) 0.30F 1.0 0.25 1 TI (a) Find the equivalent capacitance between the terminals F (b) Find the charge stored on the positively charged plate of each capacitor 0.3 capacitor HC 1.00 HF capacitor 0.250 pt capacitor HC Luc (c) Find the voltage across each capacitor 0.3 F capacitor 1.00 t capacitor 0.250 pt capacitor (d) Find the total stored energy
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Answer 1

0.30MF Ams? 0.25MF 1.oup C3 V28.6V a) 2 equivalent capacitance 1.0MF and 0.25MF are connected in paralle!! So cp 1.OMF+ 0.25117 (p= 1.25 ME 0.3MF and cp are in series so 0.30x1.25 9.30 +1.25 ceg = 0.241 MP b) Total charge oacy = 0.94 % 8.60 = 2.078 MC charge stored on 0.30MF Capacitor is Q,-0.3 = 2.072 Mc voltage drop across 2.078 M ܢܘ ܟ ܙv 0-300C v>6.90 v voltage drop across paralel connection

up =vov, 8.6- 6.90v vpe1.7V charge stored on on 1.0MF capacitor is Q : C'pl.OME X1.7V [Q2 = 107.MC) charge stored on o. QMF capacitor is C3Vp = 0 QMF * 1.7V Qz = 0.31 Mc voltage across 0.3MF capacitar is [v, = 6.900] voltage across Home and 0.2MF capacitos [V2 = V3 = 1.70] In paralled voltages are same is d) Total energy stored in capacitors € = cv² - % *0.841 MFX (8.6) E-8.9) MJ