Question

A small rocket (because I like rockets) of mass 1 kg and thrust capability of 250 N is slapped onto the edge of a large wheel. The wheel has a mass of 20 kg and a radius of 0.75 m. You light the fuse, stand WAY back, and watch as this Chinese-style firework wheel starts to spin as the rocket fires. Calculate the time it would take the wheel to spin up to 10 revolutions per second. HINT: This problem technically has TWO spinning things: the wheel and the rocket. You can treat the rocket as a point mass stuck on a stick. This will change the moment of inertia of the wheel slightly. Be sure to account for it! 3.7 sec 0.63 sec 0.60 sec 4.0 sec

Answer 1

The wheel is taken as ring shaped.

ܒܟܒ F >900 Moment of inentia of the combined system, R I Io wheel + Irocket 2 mwheel by Da + Mnocker Wheel is shaped. (20 + 1) (0.75 kg-ma Z 11.8125 kg-m2 Torque, 7218x7') = af sin goº (: the angle between s and F is 90° ZDF z 0.75 X 250 Nom 1815 Năm ( angular accelaration 7 I 187.5 We know, Te I a Where, az e laration) >> a 2 15.873 pad/s 11.8125 Starting from zero angular velocity, the wheel reach 10 revolution per second. So, W = 0 + xt (: initial angular velocity is zero TOX 217 7 t ? 3.955 ñ 4 sec. 15: 873 to S 2