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If 30 g of gold (of specific heat 0.0.03 kcal/kg ∙ °C) at 110°C is put...

If 30 g of gold (of specific heat 0.0.03 kcal/kg ∙ °C) at 110°C is put into 75 g of water (of specific heat 1.0 kcal/kg ∙ °C) at 0°C. What is the final temperature of the mixture?

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Qlost - Qga moor m SAT) 30x 18 x 0.03x18 110-T)- 75x14 4x14. (T) 30X0.03 x110 =75T + Box0:03T. х T 3ox 0.03x110 75+3oxo.og f

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