Claim : The proportion of prevention of divorce is at least 76%
P ≥ 0.76 vs P < 0.76
Given : x = 166, n = 230, p = 0.76 , q = 1- p = 0.24, = x /n = 0.7217
Test statistic:
Z =
=
= -0.0383 / 0.0282
Test statistic Z = -1.36
P-value :
As H1 contain < sign , this is left tail test,
Therefore p-value be the area on left side of z = -1.36
P( z <-1.36) = 0.0869 ------ [ from z score table ]
P value = 0.0869
Decision: Level of significance α = 0.05
As P-value is greater than α= 0.05 , we fail to reject the null hypothesis H0
Conclusion: There is no sufficient evidence to reject the psychologist's claim that the proportion of married couples for whom her program can prevent divorce is at least 76%
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for...
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 76%. In a random sample of 250 married couples who completed her program, 186 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 78%. In a random sample of 245 married couples who completed her program, 173 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance? Perform a one-talled test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 76%. In a random sample of 250 married couples who completed her program, 188 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 80%. In a random sample of 245 married couples who completed her program, 183 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.1 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
A psychologist specializing in marriage counseling calms that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 76%. In a random sample of 215 married couples who completed her program, 149 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 77%. In a random sample of 240 married couples who completed her program, 182 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places...
Time Remaining 54:35 S tempt 1 of 1 A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 77%. In a random sample of 225 married couples who completed her program, 166 of them stayed together. Based on this sample, can we reject the psychologist's daim at the 0.01 level of significance? Perform a one-tailed test. Then fill in the table below F Calculator...
Homework 13 Eming = Question 1 of 3 (1 point) | Question Attempt: 1 of Unlimited A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 76%. In a random sample of 250 married couples who completed her program, 179 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.01 level of significance? Perform a one-tailed test....
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