Question

Biofeedback Control (sample 1) (sample 2) n 99 93 X 13.8 4.0 s 1.34 1.30 Using the smaller of the two df values in the t-table closest to the calculated df, construct a 95% confidence interval for the difference in mean response. Round all calculations to the nearest hundredth. (6.1. 13.5) 19.43, 10.17) None of these (-5.0.9.0)

Answer 1

n2 ni and 30 So that we use z-test, not (t SE 32 S2 SE (1.34)2 (1:30) 93 + = 0.1905 40-18: for 954. of confidence, 24/2 = 1.96. The Margin of carrer E = 20/12 (SE) = 0.3734. 20.37. The 95% confidence Internal is (x-2-E, atret E) = (13.8-4.0-0-37, 13.8-4.0+0-37 = (9.43, 10.17)