Question

The average intensity of solar radiation reaching the surface of the Earth is 1370 W/m2. What is the peak value of the electric field associated with this radiation? 716 N/C 1020 N/C 1850 N/C 2840 N/C 5000 N/C

Answer 1

peak electric field = (2I / c$\epsilon$_o ) ^0.5

where I = intensity

c = speed of light , $\epsilon$ _o = permittivity of free space

E = (2*1370/ 3*10^8*8.85*10^-12) ^0.5

= 1016 N/C

rounding off is is 1020 N/C