Question

Question 1 < 1 of 3 Consider the beam shown in (Figure 1). Assume A is fixed supported, B is a roller, and C is a pin. Er is constant. Suppose that w = 11 kN/m. Part A Determine the internal end moment MAB acting on span AB at measured clockwise. Express your answer to three significant figures and include the appropriate units. Enter positive value if the moment is clockwise and negative value if the moment is counterclockwise. μΑ ? MAB = Value Units Submit Request Answer Part B Determine the internal end moment MBA acting on span AB at B measured clockwise Express your answer to three significant figures and include the appropriate units. Enter positive value if the moment is clockwise and negative value if the moment is counterclockwise. IT HA Figure ? < 1 of > MBA = Value Units Submit Request Answer 80 KN Part C Determine the internal end moment MBC acting on span BC at B measured clockwise. Express your answer to three significant figures and include the appropriate units. Enter positive value if the moment is clockwise and negative value if the moment is counterclockwise. HA ?

Answer 1

Ang || KN/m BOKN Ob es A С unknown gm 3m 3m B Fixed end memert WE KN/m (TTT) FEM BA 22 با 11 x 92 z z 4485 20 20 KNn 9m - llxg2 30 FEMAB = -6072 30 2 29.7 KN-M - z Be 80KN CH 3m 3m FEM Be= 3P T6 80X6*3 16 -go KN-m slope deflection equation for AB MAG= REF ( 20A +OB-30/7+ FEMAR BA=0, A=0 MAB= 2 EI COB] - g 29.7. o MBA- 2 ER g [20B to] + 44.55 MBA 4EI DE + 44.55 9 Modified slope deflection equation AB MBC BEI L (OB- 2] + FEM BE 11 MBC BEC 6 OB gu 3)

Joint B MBA + M BC =0 4 ELO 9 + 44.5+ EL dB - 90 = 0 48-123 OB = EI MAB= § Es ( 48:123.-) - 29.7 EI MAB= 19.006 kwam MBA - 9 Ex ( 48 12 3 + 44.55 EL MBA = 65.938 knom MBC = {ec ( 4823 ) – 90 MBC = - 65.938 kv.m