Question

Assigned Media Question Help According to Newton's Law of Cooling, if a body with temperature T, is placed in surroundings with temperature To, different from that of the body will either cool or warm to temperature Tit) after t minutes, where T(t)= T, - (T. - To je A cup of coffee with temperature 120°F is placed in a freezer with temperature 0°F. After 5 minutes, the temperature of the coffee is 80°F. Use Newton's Law of Cooling to find the coffee's temperature after 10 minutes After 10 minutes the coffee will have a temperature of F. (Round to the nearest integer.)

Answer 1

-kt using e-5k 280 = 3 120 0.4054 = -5k ene Lexline Gren T(+) = Tot (T.-To) e Here T=1207 To = of T(5)=80°F T(10) = ? above formulae -k(5) T(5) = Tot (Ti-Toje 80= ot (120-o) é -5k 80 = 12o é 5k е In both side Taking .5k ene ene anchenet 7 0.4054=75k k= 0.4054 0.081 Now we want the temperature after lomnat - 0.081 (10) : TLO)= of (120-0) e -0.810 120e 53.3829 to nearest integer 53.3829 ~ 53 After 10 minutes the coffee will have a temperata 53 f 2 - Now Rouncing to