Question

A 1.2-m wire carries a 0.50-A current in the northerly direction in a region with a 1.0x10^-5T magnetic field pointing 25^o east of north. What is the magnitude of the magnetic force on the wire?

Answer 1

• The current carrying wire exerts a magnetic field ,so the magnetic force on wire has to be found out using the given parameters.
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  F=ILB sin e
  
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• Angle between wire and magnetic field; LENGTH OF WIRE
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  East Of NORTH 2 B I 25° We know that Force on a current carrying wire. P = i (I x B) i= current on wire I = Length of wire BE magnetic field strength È = i Lb sono Ben substienting the value get, F = 0.50 * 2 * 1x 10-5 x sin (25) 0.50 × 1.2x 1x10-5 x 0.42261 11 0.2535 66 x 10-5 N