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Question 9 Find the values of p for which the series is convergent. Not yet answered Marked out of (-1) Σ n=2 (in(12) 3.00 P

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Solutions GO n=2 [lu (1²)] it is an alternating sereis = Here (9 и с then Unti [lu (42)] [ln (1+2) ²] P P ln(n² a Bu(n+1)?

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