Question

QUESTION 3 For the circuit shown below, all resistances are in Ohms. R1-201 R2-150 R3-250 R4-50 R5-76 V=9.00V a) What is the total resistance in the circuit? b) What is the total current in the circuit? c) What is the voltage across RS?

Answer 1

concept ohms law. V=IR Resistance en Seules R1 + R2 + R3+ --- Resistance in parallel I It ㅗ ttt Req RI R₂ R₃ Ri -2012 R3=2502 R4=502 R2=1501 9V $85=752 Solution bautla) R2 R3 R4 are in series so R234 = R2 + R3 + R4 = (150 +250 +5011 R234 = 4502 Ri and R234 are in parallel I R R234 till + ㅗ R. R234 R = (R234) (RI) - 6450) (201) (R234 +R1) (450+201) R=138-9422 av

R R and R5 are in seu's R5 Req = (138-94+75)2 Req = 213-94.2 Reg.22141] Equivalent resistance of arout (6) Total current (I) Rea w V=I Req I - V R V- pot' differente across arut VeqV I 9 A= 0.062056A 214 I= 0.0421 A Ans Total awwien SR5 (c) from fig cument supplied = 0.0421A by battery VR5 = IRS = Voltage across Rs VRS=0.0421)(75) Ves- 3.157 TVes= 3.16V option (B). Totale Resistance is 214.2 is correct AU Option CI) Total current is 0.0421 is correct Ans option (o) Voltage across Rs is 3.16 V I