Question

A. An 53,000 L swimming pool is filled with water. If deuterium is 0.0128% of natural hydrogen, find the energy released in 10¹⁴ joules if this deuterium is fused via the reaction ²H + ²H → ³He + n. Hint: this reaction releases 3.27 MeV of energy each time deuterium is fused.

B. Calculate the radius in femtometers of an atom with 132 nucleons.

C. A ⁶⁰Co source is labeled 4.1 mCi, but its present activity is found to be 2.49×10⁷ Bq. What is the present activity in mCi?

D.Calculate the number of grams of deuterium in an 68,000 L swimming pool, given deuterium is 0.0162% of natural hydrogen. Assume that the density of water is 1 kg/L.

E. Calculate the energy in MeV released in a β⁺ decay of ²²Na. Assume that the masses of ²²Na and ²²Ne are 21.994497 and 21.990439 u, respectively.

Answer 1

A let is consides a reaction, 2H +2H 73 Hein Cuilen that, į Volume = 53,000L Am = 662.013553) - 3.016049 -1.608645) -0.0024120 NOW, Ezomc2 20:00 2012 x 2 az 1493115 mevic? E-0.0024)2 xc x931.5 tihovice = 224 Mev. E- 3.5x1035 3) let els consider, 8=80 All = 1.28105x61322 = 6110x15's 8 = 6.10fm 13 C) The present activity (A) = 2.49x107B2 (ici 3.781 01039, :10'=3,7x100 = 6172x10' cé =0.672 mi

d) mass of hydrogen - volume x density - 68000 t X 100091L Amount 29. en 68000,0009 = = 68000,000 g of hydrogen en 189 So, amoint of Hz Ş& * 68000,0009 :100 GH-0.016290 REX 68000,000g = 0.0162 x 29 68000,000g 100X18 1224g.