solution:-
1. P(x = 4) = 0.027
2. P(x ≥ 2) = P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5)
= 0.306+0.129+0.027+0.002
= 0.464
3. P(x ≤ 1) = P(x = 0) +P(x = 1)
= 0.172 + 0.363
= 0.535
4.expected value
=> (0*172+1*0.363+2*0.306+3*0.129+4*0.027+5*0.002)
= 1.48
5. standard deviation
=> sqrt((0^2*172+1^2*0.363+2^2*0.306+3^2*0.129+4^2*0.027+5^2*0.002)-(1.48)^2)
=> 1.0196
The attached table describes the number of adults in groups of five who reported sleepwalking. The...
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