Question

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 21 subjects had a mean wake time of 100.0 min. After treatment, the 21 subjects had a mean wake time of 77.2 min and a standard deviation of 23.4 min. Assume that the 21 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 100.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment 68.4 min << 86.0 min (Round to one decimal place as needed.) What does the result suggest about the mean wake time of 100.0 min before the treatment? Does the drug appear to be effective? The confidence interval the mean wake time of 100.0 min before the treatment, so the means before and after the treatment a significant effect result suggests that the drug treatment Click to select your answer(s) and then click Check Answer All parts showing Clear Check AWE

Answer 1

p> given Sample mean (1) = 772 Standard Swallow (5) - 23.4 Sample size AS AS (o signa is unknown for population mean cul U= * I *. f f in At 90 % confidence to 1-0.90 1- 0.90 0.0 dh 11-1 Tip = 0.05 +60-05,90) - 1.72 [using t-table So 90.7. confidence internal U=XI triando su un 1:77-2 + 1.72 x 23.4 251-121224 u = 77.2 ± 8.81 [ 68.39, 86.01] A 901. confielence citeerd estimate of the mean wake time for a peptiklion with the treatment 68.4 I min < u 186.0 min Confidence Intwal dass net contain the mean Wake time of 1000 min before the treatment, so the means before and after the treatment au cliffecent thus result suggests that the chug treatment has a sigrafirant effet.