An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...

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An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric field with strength 4.7E+04 N/C, as s

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Answer 1

Answer #1

ЧЕ uu 4 -19 2x 1-6x 10 x 4.7 x 10 a= *lu 2 27 16% 1.66 xlo 11 5.66.3x10 m/s² a= d to v 0.17 Sec. to 2. gx10² 05 See to 5.862x

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An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...

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An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...

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An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...

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Add Answer to: An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...

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An O2+ ion (16 amu) with a velocity of 2.9E05 m/s enters perpendicularly to an electric...