Question

A pump station must fill a 15-million-gallon tank within 10 hours. The pump must overcome a total head of 115 feet (this include both elevation head and friction). Assume the pump and motor efficiency are 0.75 and 0.90, respectively. Water temperature is 80 °F. Assume the cost of electricity is $0.22/(kW-h). What is the yearly cost to operate the pump station? Round your answer to the nearest whole dollar. (Conversion factor: 1 horsepower = 745.7 W)

Answer 1

Answer:

1 Flow rate a = 15x 10o gal 10x6omin Q = 25000gpm = 55.7 +3/s. here, igpm 20.002228 ff3/sec =) At sof Unit weight of water, ht of water ww = 62.217 eb/ft 3 =) Power required by pump, Pa yw Q. Hp -Пр Иm 62 417 x55.7 x 115 کی 0.75X0.90 P 590416.2867 lb-ftls here - I HP 550lbftls P= 590H16.2867 550 = 1073. H8 HHPX 0.7457 kW P 800.497 kw For one year total time for which pumpis operated; - 365 X 1ohor, Electricity unit 800. 4197 * 365410 =8921814.5H8 kw-ha - Total cost = $0.22 x 29218164.5418 $642799.2 Total cost $642800