Question

this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit Eignment Scoring best submission for each question part is used for your score. DETAILS MY NOTES A proton travels with a speed of 5.10 x 10 m/s at an angle of 61° with the direction of a magnetic field of magnitude 0.170 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? N (b) What is the proton's acceleration? (Give the magnitude.) 1 m/s² Submit Answer View Previous Question Question 11 of 20 View Next Question Home My Assignments Request Extension BI w Type here to search

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Answer 1

Ang : Given data: The speed of the pooton v= 5.107 108 m/s angle between velocity and direction of magnetic field bi magnetic field magnitude of B0.170T magnitude of force on the proton is F=qvB sino 9 charge of proton = 1.6810 ta 1.6X10 19 X5. 10x106 m/s x 0.170 Tx sinsi Fa -13 1.213 X10 By newton's second law, the force can be calculated Fama mass of proton : 1.678 16 21 kg 1.213x16'30 = 1.67x1027 kg xa 1.213 x 100 9.67X10²Tag +13 a r7.263 X 10mis? acceleration of proton (a = 7.863x 103 mish

Ang : Given data: magnitude of magnetic field B-0.04557 radius rallomm 20.001) m For proton, the centripetal force required for circular motion is provided by the magnetic force Em fc quB sino where o=a8 QUB charge of proton q = 1.681019 mass of the proton m = 2.67*10?? kg ner = mu? mohlo So vaq Brim Vo (1.6x1019) C0.0455) (0,0011) 1.67 X10-27 kg N=4795. 2o mis