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The uniform rods AB and BC weigh 2.2 kg and 3.6 kg, respectively, and the small wheel at C is of negligible mass. Knowing tha

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The momentum is, 1 - (2.2)(0.36) =9.50x10-2 kg.m? 513CLsc I = 12 (3.6)(0.6) 12 = 0.108 kg.m? = 0.11 kg.m? U, =W4BH AB+WBCHBC1 1 1035C T= 1,038+5mgco? + = (9.50x102) 1 1 VB 0.6 VB (3.6) 0.36 = 0.9665v Using conservation of energy T1 +U, = T U2 (43.87

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