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The scores on a psychology exam were normally distributed with a mean of 62 and a standard deviation of 9. A failing grade on

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Answer #1

Solution :

Given that ,

b) P(x < 44 )

= P[(x - \mu ) / \sigma < (44 - 62) / 9 ]

= P(z < -2.0)

Using z table,

= 0.0228

percentage = 2.28%

Approximately 2.3% of the students failed

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