Question

For the beam shown, use the Conjugate Beam Method to determine a) The deflection at F, b) The slopes on both sides of the hinge at C. 90 KN 160 kN.m E B D F A 2 m ! 2 m 2 m 2 m + 2 m + 1 1 EI - Constant

Answer 1

qot 160 km Р А2 . А А 24 m им Вm c X hinge qok Ке Iko А 4 + 2м 2 2 2. В 2. 12. Вс RE ді for figiu ха гр. Ret RE 2 O 27. =0 + - Rex 4 + 60 = 0 RE - 40 KN де - 40 С о во IBMD б A B D Р F 80 — 160 --Ro - 20 2 O 12- = 40 х 2 = Во . mot Me MB 40X2 2 RO ІІ А = 40x4- 180 = - 2.0 — 90

conversion A 4 2 ܠܠܠ L 2- a B free. Internat EI Development of conjugate beam- Toading : BMD/EI 80/EI 99%E1 support hinge free fixed fined Internal roller hinge -- 80/81 Internal hinge Now, Deflectim at an = Moment at that point Roatation at any any e Shear force at that point for AB part 1.6 m. → Roller. any point ce. point 80 20 or. u 2-x x= 8961 8967 RE at A Oolm + 2m im 1.6m Dam 21. B. -20 EJ Re RE ران) زه -80 EL

Σ for figure il 5 ★ - 0 Ret RE 20 0 4 +. . XBO 2. t -X28.80 C& t X 2. 개 E1 -30 X X24 EI 140 EI 세 =O +) REX 8 - - X + + x 8 x2 ( 14 ) PI 첫음자의 어 4 24(2+) - x 3 1.4 x10-44 24 80 文 2 정 도 + 늘 X 20 EI X0.4×0.4 ㅎ BE t91S= दि PI 매 67 E1,