Question

Calculate the concentration of 103 in a 3.46 mM Pb(NO3)2 solution saturated with Pb(IO3)2. The Ksp of Pb(IO3)2 is 2.5 x 10-13. Assume that Pb(IO3)2 is a negligible source of Pb2+ compared to Pb(NO3)2· [103] = M A different solution contains dissolved NalO3. What is the concentration of NalOz if adding excess Pb(IO3)2(s) produces a Pb2+ concentration of 1.50 x 10-6 M? concentration: M

Answer 1

The concentration of IO3^- = 0.85 × 10^-5M

2. Given that Грь 1. - 50 x 106 м ksp (рьба ) - 2.5 х 10 - 13 k5p(РЬ II б ))) - Ірь?1] [10, 12 Сго, 1? . ksp (Pь (105 ),) Гр, 11 3 2.5 х 10 -13 1 •5x 0 -6 го, т. 601x101 [10; 12 - овах)0-4м [Pb(ID).] : 2 гры 11 - 2х1.50 10 6м - 3x 10 м Tut hаl [10; 1 = Pb(105).] - LibJ poduced by posita) 1556cfalsoo o Na I03 - 083 х10 4. Зя от Јо, у ГID, J = 4.08 3х10-нЗА Ј0 м +-05 3х10 нм [NAJD3] - [ 103-J produced by partial dessocpatron of NaI03 '. ГN103]. н. 053 х 10-УМ

The concentration of NaIO3 = 4.053 × 10^-4 M​​​​​​