8. ( 5 pts.) Given that the electronegativity values
for the elements Cr and S are XCr = 1.66 and XS = 2.58, the partial
ionic character of the Cr – S bond within the Cr2S3 unit is:
(a) 0.191 (b) 0.895 (c) 0.702 (d) 0.335
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
8. ( 5 pts.) Given that the electronegativity values for the elements Cr and S are...
Given that the electronegativity values for the elements Cr and S are XCr = 1.66 and XS = 2.58, the partial ionic character of the Cr – S bond within the Cr2S3 unit is: (a) 0.191 (b) 0.895 (c) 0.702 (d) 0.335
8. (5 pts.) Given that the electronegativity values for the elements Cr and S are Xca= 1.66 and Xs = 2.58, the partial ionic character of the Cr - bond within the Cr2S3 unit is: (a) 0.191 (b) 0.895 (c) 0.702 (d) 0.335
Multiple choice: 3. (5 pts.) The oxidation of copper metal by iron (III) chloride used in the etching of circuit boards goes as follows: 2 Fe3+ (aq) + Cu (s) → 2 Fe2+ (aq) + Cu2+ (aq) The reduction potential for the Fe3+/Fe2+ and Cu2+/Cu pair are +0.772 V and -0.340 V, respectively. The concentrations are [Fe3+] = 1.24 M, [Fe2+] = .248 M, and [Cu2+] = .342 M. The electrical potential for this cell at 25.00C is: (a) +1.057...
9. (8 pts.) Four atoms were arbitrarily labelled D,E,F and G. Their Pauling electronegativity values are as follows D=3.5, E-3.3, F-2.4 and G-1.3. These elements form the following species: DD, DE, DF and DG a. Arrange the four species in order of decreasing covalent character: least covalent most covalent b. Of the four species, which is/are: ionic polar covalent nonpolar covalent
Polarity Electronegativity and Dipoles CHM113 Chapter 8 Resource Worksheets Resource 2: Polarity, Electronegativity, Dipoles 1. Label the bond in each of the following compounds as ionic, nonpolar, or polar covalent. a) F2 b) HF c) KCI d) Cus 2. For each covalent compound below. Inbel the bond as either nonpolar covalent or polar covalent. Compound Bond Type Compound Bond Type NO O; Cl2 NO; PO, ΝΗ, H0 CH SO: N, NF; CCL 3. For the following compounds identify what has...
11. Given the values for H (2.1) and Cl (3.0), calculate the electronegativity difference in a hydrogen chloride bond, HCl. 36) ______ A) -0.9 B) 0.9 C) 5.1 D) -5.1 E) none of the above 12 A sample of krypton gas at 75.0 psi expands from 0.100 L to 0.450 L. If the temperature remains constant, what is the final pressure in psi? 37) ______ A) 0.167 psi B) 16.7 psi C) 3.38 psi D) 75.0 psi E) 338 psi 13. Which of the following...
Please help me do these 1. Draw the following bonds and label the electronegativity values of each atom. 2. Label the charge (8* or 8') on each atom in the bond (if they exist) and classify the bond as non-polar covalent, polar covalent or ionic. a) H-CI b) C-H c) NHO d) I-Br c) M-5 e) Mg-S DPH f) P-H vcc g) C-C m) AlH h) Al-H
8. Using the cell notation Cr3+ (aq, 0.0150 mol/L)/Cr(s)|| Pb(s)|Pb2+ (aq, 0.0355) A. (10 pts) Complete the table below for the cell as written in the above notation. B. (5 pts) What is the balanced net ionic equation represented? C. (10 pts) If the cell is constructed, what is the cell potential initially measured. Assume 25.00°C D. (5 pts) is the reaction spontaneous as written? Why or why not? (10 pts) If the cell is permitted to proceed to equilibrium,...
please help and show work! D Question 21 8 pts What is the percent yield of Cus for the following reaction given that you start with 15.5g of Na2S and 1218 CuSO4? The actual amount of Cus produced was 3.05 g. Reaction: Na2S + CuSO4-Na2SO4 + Cus • Previous Next → No new data to save. Last checked at 6:06pm Submit Quiz We were unable to transcribe this imagecalculation questions. The periodic table: periodic table aug 2019 final-2.jpg Question 23...
Question 5 8 pts Use the molecule given below to answer the following question 3 8 UD Choose the option that best describes the strength of the indicated bonds (where 1 is the strongest bond, then 2, then 3 and 4 is the weakest bond) А ✓ Choose 3 2 1 B 4 с [Choose) D [Choose] 12 pts