Question

A charge of 20.0-μC is held fixed at the origin. A -5.0-μC charge with a mass of 10.0 g is launched (outwards) from the position (1.0 m, 1.0 m) at a speed of 12.0 m/s. (a) At what distance from the origin will its speed be reduced to 6.0 m/s? (b) Will it ever halt? If yes, at what distance will it halt?

Three point charges are located at the corners of an equilateral triangle, whose side l = 0.5 m. The charges have magnitude -7.00 μC, 2.00 μC and 2.00 μC respectively. (a) Calculate the total electric potential energy of these charges. (b) How much work must be done to move the 2.00 μC charge to infinity, leaving the other two charges in place? (d) Find the (net) electric field at the midpoint between the 2.00 μC and -2.00 μC charges.

Answer 1

UBE Q riya To 9, = 20 ya bonbon 92 to-suc q z= AU,1) ú 8=8A=5am 4=12m5's 0 10,0) OVI would The pre- of the syetem orilor Corresponding to the confeguration (0-A1 axio xzoxsxroth F2 1,-0.6364J PE=U = krig ri 7) Kenetic energy KE, = timu txl10x103) x144 KE=0.72J 03=82 for the Confeguration 10-B) KG2=&me²2x110x103)*36 0:18J Uz = korea2

Apply Conservation of mechanical Energy Uz + KEz = Uitke, Uz = Uitke,-KEL 0-6364 +0.2 -0.1% - 00964 U2 = -tek 76 67 Garo * 2005 2014 V 8₂= -0.0569 82=9.34m. e-co teibt be )=8 To BE (6-6, 6-63m 2 ke at yes it will halt, let at a distance &z from the oregen Oc=83, at pont & the koleg the speed of qs will be zero Therefore c es kez Uitke, a U3+KE33 CU,AKE, = -0.0836 K9,9 -0.08367 82 _90109x20x5xiola 0.0836 183=10.77m c= (-0,10->>) -(7.6,306) * Uz = Ee