Question

A presidential candidate's alde estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60%. IF 114 out of a random sample of 220 college students expressed an intent to vote, can we reject the aide's estimate at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. a H P The null hypothesis: . 1x s The alternative hypothesis DO OSO 020 The type of test statistic: (Choose one) DO The value of the test statistici (Round to at least three decimal places 0 6 ? The critical value at the 0.05 level of significance (Round to at least three decimal places.) Can we reject the aide's estimate that the proportion of college students who intend to vote is at least 60% o Yes NO

Answer 1

X Given 114 Claim р 220 point estimate for the proprotion p = x/n n a. 0.60 0.05 0.5182 Test hypothesis are Ho: P 5 0.60 Ho: P 0.60 Critical value Za/2 1.645 NORM.S.INV(1-a) (Uisng excel) Rejection region reject H, if z> 1.645 Test statistic z= (-p) p(1-p)/n) -2.47717 = -2.48 p-value =P(z>20) 0.9934 T.DIST.RT(to,df) (Uisng excel) Since test statistic is not greater than 1.645 hence fail to reject the null hypothesis

Answers are Null hypothesis. Ho: p=0.60 or H:P <0.60 Alternate hypothesis , Hi: p > 0.60 Type of the test are : 1 proportional z test Test statistic z=-2.48 Critical value z = 1.645 No