Question

What is the heat capacity at constant volume, Cv, of an ideal gas, in ??? ?? °? if the constant pressure heat capacity, Cp = 0.124 ?? ??? ? and the molar mass of the material is 28 ton/ton-mole?

Answer 1

Volume respectively. R- Universal go constant ce and CV are opecific heat al presure and constant 8.314 K5 kg molek Id con 8 teme Cp = 0.124 KJ mol- kelvin 1 mol = 10-3 kg-mole. * expressing Cp in KJ Ko melk 0.124 kJ x 103 mol mol kg-mole - Cp = 124 KJ Kg-mel kelvin- cei 2 * Now using the relation; .R Cp - Cv - Cv = CP-R cv = (124-8-314) KJ K8 mole - k - Cua 115.686 KJ Kgmolek M = Molecular weight of of material M = 28 ton ton-mole (ton tonton mole)

1 tom = 103 kg. * Expressing ton ton-mole M = 28 ton ton-mole Kg kg-mole 28 * 103 kg * ton 103 kg-mole ton 28 Kg 4 kg-mole. * Expressing Cv in KJ kg-k - Cu = 11S. 686 KJ Me kg/kg mote] ho Cu LIS: 68 6 28 kg-mol-K KJ kg-K Cv a 4.1316 KJ Ko-K * Converting K&K Btu lb-R 1 KJ = 1 kg = 1k = 0.9478 Btu 2.204 lb. 10.5556 • R .