1. Of the four methods use to estimate the roots, which one appeared to be fastest (take the fewest iterations) to arrive at a solution:
a)False-position method
b)Bisection method
c)Secant Method
d)Newton’s Method
e)They all took the same number of iterations
2.The Bisection and False-position method are:
a)Interval (bracketing) methods
b)Calculus-bases methods
c)Secant methods
d)Uses Ohm’s law
3.The Secant method is similar to Newton’s method except:
a)for the use of an approximation for the tangent-line
b)that two points (defining the Secant-line) are stored and updated
c)Both A and B
d)Neither A nor B
4.Using Newton’s method to solve 3x-6=0 for x. If you choose an initial “guess” x=0, how many iterations will the solver require to converge with a tolerance of 10^(-9)?
a)1
b)2
c)3
d)Never converge
5.Using Newton’s method to solve (x^3)-8=0 for x. If you choose an initial “guess” x=0, how many iterations will the solver require to converge with a tolerance of 10^(-9)?
a)1
b)2
c)3
d)Never converge
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1. Of the four methods use to estimate the roots, which one appeared to be fastest...
The Bisection and False-position Method can be used to solve linear systems of equations Ax = b True False fzero() will converge to the root for any initial guess. True False The number of iterations required to find the root via the Bisection and False-position methods increases as the tolerance value decreases. True False
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