Question

In an exit poll, for which the sample size was 3110, suppose that 45% of all voters voted for a recall. Answer the following questions. a. Define a binary random variable taking values and 1 that represent the vote for a particular voler (1 = vote for recall). State its probability distribution. Choose the sentence below that best describes the probability distribution OA. For each random sample of 3110 people, about 1400 people voted for recall and 1711 did not OB. For each random sample of 3110 people, about 1711 people voted for recall and 1400 did not. OC. The binary random variable is the vote for the recall with yes or no. For each observation, P(1)=0.55 and P(O)=0.45. OD. The binary random variable is the vote for the recall with yes or no. For each observation, P(1) =0.45 and P(O) = 0.55 b. Find the mean and standard deviation of the sampling distribution of the proportion of the 3110 people in the sample who voted for the recall - (Round to two decimal places as needed.) standard deviation - (Round to four decimal places as needed.) mean

Answer 1

Answer:

a)

Given,

sample n = 3110

p = 45% = 0.45

Option D

b)

Mean = p = 0.45

Standard deviation = sqrt(pq/n)

substitute values

= sqrt(0.45(1-0.45)/3110)

= 0.0089