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Write the expression as a single logarithm. 1 2 loga (6x) - log (2x+15) 14 36x 2 loga (6x?) - log a(2x+15)= loga 1 9 (2x + 15
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Answer #1

2 log bxt - 12 loge ( 2x+6) da = loga (ox7) а (эм+ 10) sloga= logan 36x!! To7 (э» ку: 14 3Gх ~- (о 2 b 1 - (2x+5), Correct

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Answer #2

SOLUTION :


2 loga (6x^7) - 1/9 loga (2x + 15)

= loga (6x^7)^2 - loga (2x + 5)^(1/9)

= loga ((36x^14) / (2x + 5)^(1/9) (as indicated) (ANSWER).

answered by: Tulsiram Garg
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