Water flows through the channel. The depth of flow is y =1.75 m and the downward slope of the channel is 0.006. The sides of the channel are finished concrete. (Figure 1)
Part A
Determine the volumetric flow of water through the channel.
Bottom width B = 2 m
Depth of flow y = 1.75 m
Side slope z = 1 horizontal : 2 vertical = 0.5
Area of cross section of channel A is given by:
A = (B + zy)y = (2 + 0.5*1.75)*1.75 = 5.03125 m2
Wetted perimeter P is given by:
Hydraulic radius R = Area of cross section / Wetted perimeter = A/P = 5.03125 / 5.913 = 0.85086 m
Bed slope S = 0.006
Manning's coefficient for finished concrete n = 0.012
Volumetric flow through the channel is given by:
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