Question

A squirrel jumps from the top of a tree which is 3.40 m high into Tallula's backyard with the initial velocity of 18.58 m/s at an angle of elevation 27.64º. a) Draw a labelled diagram to show the motion of the squirrel. (1 mark) All the information provided in the problem must be shown in the diagram. b) Calculate the time it takes for the squirrel to hit the ground, in seconds. Correct "time" value (1 mark) Showing all calculations in detail, step by step (4 marks) . . . c) Calculate the horizontal range of the squirrel. Enter this value, in m, to 3 decimal places in the box below. • Correct "horizontal range" value in the provided box below (1 mark) Showing calculations in detail (3 marks) . Place your OneCard on your work and use the "Genius Scan" or "Adobe Scan" annlication

Answer 1

Sol us consider the tree is 3.40 m high and angle of elevation is 27.64° 27.69 C a N/27064 18.58 mis 3.gom 27.89 3.4om 127.64 18.58 Liven initial velocity Vi = 18.58 mis Vertical velocity is given by visine 27.60) = 8.619 m/s and horizontal velocity is Vicos (27.69) = 16.459 mis h = ut that? 3.40 = (8.619) + + $ 9-81te 6.8 = 17.238 t t 9.8t2. 9.8t² + 17.2384 *6.8=0 t = 17.238 + $(17, 238 # 4x6.8 x 9.8 2 x 9,8 t=116c t = 2,090 sec ) We know the horizontal velocity. = 16.459 m/s со The range = vyt - 16.459 X 2.070 34.399 m