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Corresponding eigenvectors of each eigenvalue 9 Let 2. (as find the eigenvalues of A GA 1 -- 1 and find the or A each 5 Find

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Given 2 0 Az - 0 The eigen eig en values of A is given by the characterestin equation, 13 - 4 x² +59-220 gives, x=1,1,2. compNow for X-2 where (A-27)x=0 2 5) - 0 0 x-y-z=0 z=0 = x=y. Hence eigen vector, x= X ( Eigen space E2 = Ez=1 Spank (!) clem 2There are other arguments aswell by which you can conclude that A is invertible like algebraic multiplicity of each eigen value is equal to the geometric multiplicity. Try to find the other arguments would be helpful for you

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