Question

Question 4 5 pts A double-slit experiment has a slit separation distance of 0.06 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen, when the slits are illuminated with a laser of wavelength 532 nm, what should be the distance to the screen from the slits? O 0.68 m O 0.45 m O 1.12 m O 0.56 m O 0.77 m

Answer 1

0.06 mm 532 nin slits seperatiorlad) fringe width (B) = 5mm wavelength(s) D=? B ad we know 2D D. adoß I 2 0.068103 x 5810 532 X 10 109 D 0.56 m distance to the screen from the shit (D)=0.56 m