Question

1. Find the center and radius of a circle that has (-2,7) and (10,-9) as endpoints of a diameter. Then write the equation of the circle. (upts) center! radiusi equation!

Answer 1

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Solution: Diameter form of Circle (z - x)(x -x2) + (4-48)(y-72) 0 where (x3,4,) and (x2, 4, ) are end point of circle we have (x2.40)= (-2,7) CX3 4,)= (10,-9) Plug values =) (2+2)(x-10) + (y-7)( 4+9)=0 ze?-10x +22-20+ y?+gy - 74+63-0 -) =) 2 x +y2-8% + 24 -83 = 0 (9) Equation of circle', x² + y² 822 + 2y-83 co (b) Centre Coetticiend oft, coefficient of y) 2 2 = (-42),-?) (4,-5) Centre (4,-1)

LC) Radius a 2 2 X. Coordinate of centre ( y-coordinah of centre Mexx tuotsua) ✓ (4)²+(-85²- (-83) ་ད J Too 10 unit Radius tiun or