Question

1.) solve the problem y'=(x+1)y yo) =1 numencally for 4 (02) using hol? 2 1:21 A B 1.2 E).221

Answer 1

y = (+1) 9 1960)-1 hool (0.2) = ? from y) = (mt) y, poro, yo = 1 we know by Ewers formula gitta Geet hiffmis.) i20 g, = go the flo, 1) 7 g (poth) = g(orto. 1) = y(ood) = 14 (6.1)x1 alto.l=1.1 -> 70.;) = 11 ya = gith. frey, y) y (+34) = 0 (0+ axou) y(0.2) = 1.1 +(00). (0.1+1).1.1 7 0 (02) - 1.170-4x(64132 2. = 1.221 if y(0.2) - 1.221. Its yl-4y+4 40 Auxillary o que tedy Qeve , 3 m2-um tyco. (m-) 0 m = 2; 2 so, its solution May = (a +Gm) e 21 CScanned with C

of this radily of onvergence of the power So era ad p. eam two l. i solution differential equation. Ans: A. Σ Herce aya hel R be thee know Series, we ㅊ din / Out nyal cu? n. an lim nt! K nch - lim Mity) = 140=/ nycb So, 21 7 R1 Ans: db ( Lal, y(m) = { Gya? do gla Ž na na "" = 8 n(n-1) Can-2 y"-g E Canno 2 any 4-2 مل { nch-1) Cym"-2 no n=2 do [ +2)(n+1) Stir? - E Ger? co Ho (6+1) (n+7) Cata d E o.p. C) ea? CS > E case canner

Date: (n+1)(n+2) Cuta - 20 Cnta Cu (n+1) (2+2) na o,1, 43, 4, . n=2 1x2 u Cu G 3 x 4 C 182X 3x4 41 G = Purnal Co (n)! en 0, 79,- c'h equation k G we have 2x3 na 3 C = Ca 4x3 こ Gli Cant 2x3x6x5 G (ant!!! do ca 2012 Hoy -Emo (217) C Scanned with CamScanner Intl C + Σ G. na ant)!