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Use n = 9 and p=0.1 to complete parts (a) through (d) below. (a) Construct a...
Use n= 10 and p=0 3 to complete parts (a) through (d) below (a) Construct a...
Use n= 10 and p=0 3 to complete parts (a) through (d) below (a) Construct a binomial probability distribution with the given parameters 8 10 Round to four decimal places as needed) (b) Compute the mean and standard deviation of the random variable usingh"Ep.P(x #x-L」(Round to two decimal places as needed ) and%" x2-P(x μ (Round to two decimal places as needed) (c) Compute the mean and standard deviation, using μ' np and ơx® p(1-p) Use n- 10 and p-0...
2 Use n - 10 and p 05 to complete parts (a) through (d) below (a)...
2 Use n - 10 and p 05 to complete parts (a) through (d) below (a) Construct a binomial probability distribution with the given 10 Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random vanable using μ,-Jr. P(x) and -(Round to two decmal places as needed ) Round to two decimal places as needed.) P,-- -fp(1-p) (c) Compute the mean and standard deviation, using μ,-np and (Round to two decimal places as...
Use n = 10 and p = 0.85 to complete parts (a) through (d) below. (a)...
Use n = 10 and p = 0.85 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters. X P(x) X 0 P(x) 0 3 10 0 5 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using uy = [X.P(x)] and Oy = ound to two decimal places as needed.)
use n=6 and p=0.15 to complete parts a through d please Use n 6 and p...
use n=6 and p=0.15 to complete parts a through d please
Use n 6 and p 0.15 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters x P(x) 0 0.3771 1 0.3993 2 0.1762 3 0.0415 4 0.0055 5 0.0004 6 0.0000 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using #x-O (Round to two decimal places as needed.) x- [x-P(x) and...
f size of n 4,900 from a binomial probability distribution with P 0.50, complete parts (a) through (e) below. Given a r...
f size of n 4,900 from a binomial probability distribution with P 0.50, complete parts (a) through (e) below. Given a random sample EClick the icon to view the standard normal table of the cumulative distribution function. a. Find the probability that the number of successes is greater than 2,490. (Round to four decimal places as needed.) P(X 2,490) b. Find the probability that the number of successes is fewer than 2,425 P(X<2,425) (Round to four decimal places as needed....
Assume a binomial probability distribution has p = 0.70 and n = 400.
You may need to use the appropriate appendix table or technology to answer this question.Assume a binomial probability distribution has p = 0.70and n = 400.(a)What are the mean and standard deviation? (Round your answers to two decimal places.)
mean
standard deviation
(b)Is...
3 Ques Given a binomial distribution with n= 12 and p = 0.60, obtain the values...
3 Ques Given a binomial distribution with n= 12 and p = 0.60, obtain the values below. a. the mean b. the standard deviation c. the probability that the number of successes is larger than the mean d. the probability that the number of successes is within 12 standard deviations of the mean a. The mean of the binomial distribution is 7.2. (Type an integer or a decimal.) b. The standard deviation of the binomial distribution is 1.6971 (Round to...
Describe the sampling distribution of p. Assume the size of the population is 30,000. n-1400, p...
Describe the sampling distribution of p. Assume the size of the population is 30,000. n-1400, p 0.376 Describe the shape of the sampling distribution of p. Choose the correct answer belovw. O A. The shape of the sampling distribution of p is not normal because ns0.05N and np(1-p)210. O B. The shape of the sampling distribution of p is approximately normal because n s0.05N and np(1 p)10. O C. The shape of the sampling distribution of p is approximately normal...
(#9) Suppose a simple random sample of size n = 200 is obtained from a population...
(#9)
Suppose a simple random sample of size n = 200 is obtained from a population whose size is N = 10,000 and whose population proportion with a specified characteristic is p=0.4. (a) Describe the sampling distribution of p. Choose the phrase that best describes the shape of the sampling distribution below. O A. Not normal because ns0.05N and np(1-P) 10. OB. Not normal because ns0.05N and np(1-P) < 10. OC. Approximately normal because ns 0.05N and np(1-P) < 10....
Describe the sampling distribution of p. Assume the size of the population is 25,000. n 700,...
Describe the sampling distribution of p. Assume the size of the population is 25,000. n 700, p 0.548 Describe the shape of the sampling distribution of p. Choose the correct answer below. O A. O B. The The shape of the sampling distribution of p is not normal because ns 0.05N and np ( p)10 n0.05N and np(1-p)1 distribution of p is approximately normal because ns The shape of the sampling distribution of p is approximately normal because ns0.05N and...
Use n= 10 and p=0 3 to complete parts (a) through (d) below (a) Construct a binomial probability distribution with the given parameters 8 10 Round to four decimal places as needed) (b) Compute the mean and standard deviation of the random variable usingh"Ep.P(x #x-L」(Round to two decimal places as needed ) and%" x2-P(x μ (Round to two decimal places as needed) (c) Compute the mean and standard deviation, using μ' np and ơx® p(1-p) Use n- 10 and p-0...
2 Use n - 10 and p 05 to complete parts (a) through (d) below (a) Construct a binomial probability distribution with the given 10 Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random vanable using μ,-Jr. P(x) and -(Round to two decmal places as needed ) Round to two decimal places as needed.) P,-- -fp(1-p) (c) Compute the mean and standard deviation, using μ,-np and (Round to two decimal places as...
Use n = 10 and p = 0.85 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters. X P(x) X 0 P(x) 0 3 10 0 5 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using uy = [X.P(x)] and Oy = ound to two decimal places as needed.)
use n=6 and p=0.15 to complete parts a through d please
Use n 6 and p 0.15 to complete parts (a) through (d) below. (a) Construct a binomial probability distribution with the given parameters x P(x) 0 0.3771 1 0.3993 2 0.1762 3 0.0415 4 0.0055 5 0.0004 6 0.0000 (Round to four decimal places as needed.) (b) Compute the mean and standard deviation of the random variable using #x-O (Round to two decimal places as needed.) x- [x-P(x) and...
f size of n 4,900 from a binomial probability distribution with P 0.50, complete parts (a) through (e) below. Given a random sample EClick the icon to view the standard normal table of the cumulative distribution function. a. Find the probability that the number of successes is greater than 2,490. (Round to four decimal places as needed.) P(X 2,490) b. Find the probability that the number of successes is fewer than 2,425 P(X<2,425) (Round to four decimal places as needed....
3 Ques Given a binomial distribution with n= 12 and p = 0.60, obtain the values below. a. the mean b. the standard deviation c. the probability that the number of successes is larger than the mean d. the probability that the number of successes is within 12 standard deviations of the mean a. The mean of the binomial distribution is 7.2. (Type an integer or a decimal.) b. The standard deviation of the binomial distribution is 1.6971 (Round to...
Describe the sampling distribution of p. Assume the size of the population is 30,000. n-1400, p 0.376 Describe the shape of the sampling distribution of p. Choose the correct answer belovw. O A. The shape of the sampling distribution of p is not normal because ns0.05N and np(1-p)210. O B. The shape of the sampling distribution of p is approximately normal because n s0.05N and np(1 p)10. O C. The shape of the sampling distribution of p is approximately normal...
(#9)
Suppose a simple random sample of size n = 200 is obtained from a population whose size is N = 10,000 and whose population proportion with a specified characteristic is p=0.4. (a) Describe the sampling distribution of p. Choose the phrase that best describes the shape of the sampling distribution below. O A. Not normal because ns0.05N and np(1-P) 10. OB. Not normal because ns0.05N and np(1-P) < 10. OC. Approximately normal because ns 0.05N and np(1-P) < 10....
Describe the sampling distribution of p. Assume the size of the population is 25,000. n 700, p 0.548 Describe the shape of the sampling distribution of p. Choose the correct answer below. O A. O B. The The shape of the sampling distribution of p is not normal because ns 0.05N and np ( p)10 n0.05N and np(1-p)1 distribution of p is approximately normal because ns The shape of the sampling distribution of p is approximately normal because ns0.05N and...
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