Х Online Homework Week 4B Est. Length: 2:00:00 Seok Jin Ko: Attempt 1 Question 3 (1...
x Online Homework Week 4B Est. Length: 2:00:00 Seok Jin Ko: Attempt 1 Question 1 (1 point) Given X = 15 and 5 = 1.2, find the z- score for x = 11.4 A Question 2 (1 point) Find the probability that a z-score randomly selected from the standard normal distribution is less than -2.38. Round your result up to four decimal places. Ą 기 + 36
х Week 1 Knowledge Check Est. Length: 2:00:00 donnice salisbury: Attempt 1 Question 1 (1 point) Saved Which class of nutrients is considered a macronutrient? carbohydrates vitamins minerals Question 2 (1 point) Saved Which class of nutrients is considered a micronutrient? fat minerals alcohol Question 3 (1 point) Saved
A manufacturing process makes rods that vary slightly in length but follow a normal distribution with mean length 25 cm and standard deviation 2.60. What is the probability of randomly selecting a rod that is shorter than 22 cm? P(X<22)=P(Z< ) = Round your z-score and probability to four decimal places. The time a song plays on the radio varies from song to song. The time songs play varies according to a normal distribution with mean of 3.2 minutes and a...
Week 5 Knowledge Check x Est. Length: 2:00:00 donnice salisbury: Attempt 1 Question 1 (1 point) ✓ Saved Women are naturally inclined to wear make-up and heels. True False O Question 2 (1 point) Saved According to the Davis-Moore thesis, stratification is unhealthy for society. O True False
U.S. internet users spend an average of 18.3 hours a week online. If 99% of users spend between 13.2 and 23.4 hours a week, what is the probability that a randomly selected user is online less than 14 hours a week? Assume that internet usage follows a normal distribution. Round the final answer to four decimal places and intermediate z value calculations to two decimal places. The probability of a randomly selected person being online less that 14 hours per...
MAT305-02 UG Spring 2019 Session 1 Homework: Week 4 Homework Score: 0.4 of 1 pt Save | 1 of 10(1 complete) HW Score: 4%, 0 4 of 10. 6.2.2 Question Help Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below Click here to view page 1 of the cumulative standardized normal distribution table, a. What is the probability that Z is between-1.53 and 1.89? The probability that...
is Question: 1 pt Fand the area df he shed regon The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1 0.92 z 1.27 The area of the shaded region is Round to four decimal places as needed ) Assume that a randomly selected subject is given a bone density test. a graph and find the probability of a bone density test score greater than 1.75 Sketch the region. Choose the correct...
Question 1 Question 3 The amount of time it takes to see a doctor a CPT-Memorial is normally distributed with a mean of 48 minutes and a standard deviation of 16 minutes. What is the Z-score for a 20 minute wait? Round your answer to two decimal places. Question 2 1 pts The battery life of the Iphone has an approximately normal distribution with a mean of 10 hours and a standard deviation of 2 hours. If you randomly select...
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1 C 0.2206 z 0 The indicated z score is (Round to two decimal places as needed.) Enter your answer in the answer box Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. 0.7517 z 0 The indicated z score isa (Round to two decimal places as needed.) Enter vour answer in...
Homework: Homework #6 Save Score: 0 of 1 pt 33 of 50 (23 complete) w score: 41%, 205 of 6.4.6-T Question Help The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.6 cm a. Find the probability that an individual distance is greater than 217.50 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 202.80 cm. c. Why can the normal...