Question

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A proton and an electron enter a uniform magnetic field. The velocity vector of each particle is perpendicular to the magnetic field. If their circular orbits have the same radii, what is the ratio of their speeds (Velectron/ proton)? O 5.5E-4 O 0.5 O 1.0 04.0 1800

Answer 1

① velocity of a cheuge entering perpendicular to a magnetic field, qB N, 202 v mr qe B mer seys qe=1:6810196 qp=1-6816196 Lp B mpr ..qe=qp X mp !! qe mex qp 11 me me -29 1.677 10 9.1X10-31 Ve = 18oo (Ans) w approximately CS Scanned with CamScanner

© B = 2.5T ; L = 5 cm = 0.05m ; M = L = 5 cm = 0.05m ; m = log = 0.01kg; I = 9 w = mg Magnetie force, fa = BIL FR = BIL cupacucts) weight (downwcuids) For tension being zero, (since there are a leads) BIL I ng FC الا ng 2 BL 0.01 x 9.81 2.5xo.05 x2 0:34 A Cans) I Direction : - from left to right [using Fleming's left hand scule] Ra Ri=100 .R3 -62 R4 = 22. R2= R3 122 Ri CS Scanned with CamScanner

R23 = R2 2. olar Cpanalled) 2 = 32 RA + R23 (series) 1) 423 = 2+3 = 52 Net resistance is given by C parallel -18 R. R423 spl- 11 io N to mle olm R - R = 3.33 ohms (Ans) CS Scanned with CamScanner

Ve 4 R = 2.2 R2 = R3 = 452 ERI ا -25V R2 V = 15 V B mm Ve 20V RB From figure 2 R2 = R23 - tlar -2.32. Net sesistance, R = R1 + R23 R = 2+2 =42. Net potential, V = Vetve - VA 25 E15 + 20 lov 10 ::: Current, I >le 10 4 = 2.5 A 2 .: Power dissipated in Ri, P= I RI Pi (Ans) 2 2.5 x 2 12.5 W CS Scanned with CamScanner