Answer:
$12.06
reason: As a range of price is given for the new consideration, it is easier to consider each option and select the one that yields maximum revenue.
Formula: Ed = (Change in quantity)/ (Change in price) * (original price/ original quantity)
a) new price = $12.06:
-2.25 = (Change in quantity)/ -1.19 * (13.25/80) : So,
(Change in quantity) = 16.17.
New quantity = 80 + 16.17 = 96.17 seates are not
divisible. So the nearest quantity = 96
Revenue would be: 96*12.06 = $1157.76
b) new price = $7.40: Although this price would create the
maximum revenue because of high elasticity of demand of Silver
class, this price is below the range under consideration. (range of
new price = $11.50 - $12.50)
Also, the new quantity would be 339 which exceedss the theater
capacity of 300
(-2.25 = (Change in quantity)/5.85 * (13.25/80). New quantity would
be 159;
total seats would be: 159+180 = 339 (*) this option is not
viable
c) new price = $12.50:
-2.25 = (Change in quantity)/ -0.75 * (13.25/ 80) So, (Change in
quantity) = 10.19
New quantity = 80 + 10.19 = 90.19, nearest number = 90
Revenue would be: 90*12.50 = $1125.
d) new price = $12.17:
-2.25 = (Change in quantity)/ 1.08 * (13.25/80) So, (Change in
quantity) = 14.67, nearest number = 15
New quantity would be 80 + 15 = 95
Revenue woud be 95 * 12.17 = $1156.15
Thus the highest revenue is from option (a) with the price $12.06.
Verification. The price of Silver tickets is highly elastic. It has the highest elasticity of the three types of tickets, too. So, it only makes sense to reduce the price of the tickets to the lowest possible price in order to earn maximum revenue because the property of elasitcity states that in the case of elastic demand, when price is decreased, the revenue increases.
Therefore, out of the three feasible options, $12.06 is the minimum price. It will fetch maximum revenue.
Again, the lowest in the range under consideration ($11.50) would have brought the maximum revenue.
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