Question

Part A Two workers pull horizontally on a heavy box, but one pulls twice as hard as the other. The larger pull is directed at 25.0° west of north, and the resultant of these two pulls is 490.0 N directly northward. Use vector components to find the magnitude of each of these pulls. Assume that the smaller pull has a component directed to the north. Enter your answers numerically separated by a comma. ΟΙ ΑΣφ Submit Request Answer Part B Use vector components to find the direction of the smaller pull. Assume that the smaller pull has a component directed to the north.

Answer 1

Fi FR = 490N 25° w E 3 o F2 Fi = 2 F2 = 28 (let) For larger pull F2 smaller pull FR = F + F2 (F2 sino - Fi sinas) i + (F2 WB + Fi (6325) } = 490 F2 sino = Fi sinas, F₂ uso + F, 6325 = 490 Gea / sino = Fi sin25° = 2 F2 sin25 sino=2 sin 25° 7 o= sin(2 sinas)= 57.6970 coso = cos s 70 697 = 0.534 F2 caso + Fi Cosas = 490 F2 caso + 2 F2 6325 = 490 F2 = 490 wot 2 6925° F2= 208.811 N Fi = 2 F2 = 417.62 N Answer b) F2 is at angle o= 57.697° East of North