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The Chebyshev polynomials can be determined from Tn (2) = cos(n cos-1.).(c) Show that n! .n-2k [n/2] T(z) = 1 k= (2k)!(n – 2k)! —2k (22 – 1)“. (Note: You need to prove it in detail. To do it, you

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Answer #1

We have Tna)= cos en costx), put x = coso then we have - -ion -ion Tn (a)= cos nos Ź -ig eig n-k a n- Ne swi Swi Ewa ☆ [Closo

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