2)
Total distance travelled by Bob, D = 145 + 101 + 239 = 485 km
Total time taken for the journey, T = 10.6 hours
Average speed, v = D / T
= 485 / 10.6
= 45.755 km/h
3)
The initial speed of the cannon, u = 28.48 m/s
The final speed of the cannon, v = 0
Acceleration, a = - 9.8 m/s2
Consider h as the maximum height reached by the watermelon.
Using the formula, v2 - u2 = 2 * a *
h,
h = (v2 - u2) / (2 * a)
= (0 - 28.482) / (2 * -9.8067)
= 41.355 m
Question 2 (1 point) Bob drives his car 145.00 km [N], then he stops to get...
Bob drives his car 119 km [N], then he stops to get gas. Then he drives his car 169 km [E], and stops to eat doughnuts. The he drives his car 279 km [S], and his journey ends. Bob's trip is completed in a time of 9.61 hours. The mass of his car is 1617 kg. What is the magnitude of Bob's average velocity in km/h and the direction?
Question 3 (1 point) Bob uses a cannon to fire a watermelon straight up from ground level. The speed of the watermelon when it leaves the cannon is 28.48 m/s. The mass of the watermelon is 8.03 kg. Calculate the maximum height of the watermelon above the ground in metres. Consider up is positive (+) and down is negative (-). Answer to 5 decimal places. Do not enter units.
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Time Left 04 Question 1 (1 point) Bob uses a cannon to fire a watermelon straight up from ground level. The speed of the watermelon when it leaves the cannon is 30.8 m/s. The mass of the watermelon Is 10.02 kg. Calculate the time the watermelon is in the air in seconds. Your Answer: Answer
Instructions for PHY 2048 Problem Set (PSET): (1) Please NEATLY write your name and your solutions. (2) You must use blank 8"x11" printer paper. (3) Begin each problem on a new page, and put your name on each page. Staple your pages together. 4) Only write on one side of the page. (5) You must write up your solutions independently (i.e. don't copy anyone else's solutions), using your own words and thought process. You must show all of your work....