The lifespan of housecats is normally distributed with a mean of 15.1 years and a standard...

Question

Question

The lifespan of housecats is normally distributed with a mean of 15.1 years and a standard deviation of 1.75 years

a. Find the age of a housecat that separates the oldest 8% from the youngest 92%

b. describe the location and shaded region under the normal curve

Answer 1

Answer #1

solution Given that el=isol years. 0 = 1.25 Years. Using normal distribution table Plz> Z) = 8% = 1-pcz<3)0.08 -P( ZCZ) = 1-0

Answer 2

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