Question

Suppose that in a random selection of 100 colored candies, 30% of them are blue. The candy company claims that the percentage of blue candies is equal to 27%. Use a 0.01 significance level to test that claim. 

Identify the null and alternative hypotheses for this test. Choose the correct answer below. 

A. H0: p=0.27 H1:p≠0.27 

B. H0 p=0.27 H1:p>0.27

 C. H0 p=0.27 H1:p=0.27 

D. H0: p=0.27 H1:p<0.27 

Identify the test statistic for this hypothesis test. 

The test statistic for this hypothesis test is

 (Round to two decimal places as needed.) 

Identify the P-value for this hypothesis test 

The P-value for this hypothesis test is 

(Round to three decimal places as needed.)

 Identify the conclusion for this hypothesis test. 

A. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 27% 

B. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 27% 

C. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 27% 

D. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 27%

Answer 1

Solutions Test Hypothesis :- option is right answer Ho! P=0.27 Hai P80127 statistics! Test n=100 = 30. =0.30 z= P-Po 0.30-0.27 0.6546 POCI-Po) 0.3XO 7 too 2=0.6546 p value- At 2-0 6546 using Z distribution two tail pvalue =0.5127 reject Ho Pvalue> 0.01 fail to conclusion! option D is right answer

Answer 2

z should be 1.66.  

(0.3-0.23)/SQRT(0.23*0.77/100)

Answer 3

Using the TI-84 Plus 

Use the 1-PropZTest mode

p0: .27

x:30

n:100

Prop =p0

Calculate