Question

10. [6/8 Points) DETAILS PREVIOUS ANSWERS MY NOTES Suppose the drug atenolol is taken in 75 mg doses once a day to lower blood pressure. At the end of a 24 hour period, approximately 7 % of the atenolol is still present. (a) Find expressions for the quantities Qy, Q2, Q3, ..., and Qy, representing the amounts of atenolol in the body right after taking the 1st, 2nd, 3rd doses respectively. Then write the expression for Q, in closed-form. Q1 = 75 Q2 = 75 + 750.07) Q3 = 75 + 750.07) + 751.07) (1 –.079–1) 750.07) 1-.07 (b) Find expressions for the quantities P2, P3, Par... and P, representing the amount of atenolol in the body right before taking the 2nd, 3rd, 4th doses respectively. Then write the expression for p in closed-form. P2 = 750.07) P3 = 750.07) + 750.07) PX - 756.07) + 756.07)2 + 750.07)3 P = 750.07)1 -_071-1 1-.07

Answer 1

Q = 75 75+ 7510070) because added on that day 71. of Q, + 75 mg = 7% of Q₂ +75 007 (75+0.07*15) + 75 75 + 7510.07 + 75 (0.07) 2 This in Not 75+ 75 10-07)+ 751001) + ..t 751007) in Geometric progression initial term and 7510-07) = 0.07 L1 where a= 75 Common ratio r 75

In a "on With geometric progressio Sum of n terms ratio lg, and first term 'a given by Common S = Here for n torms 7511-0.07) a. 75 n = 8:0.07. I-0.07 P = 75 (0.07) P 3 = 7% of (P +75)_ 0.07 (75 (0.07+75) 7560.07) + 7510.07) P3 Pn= 7510-07)+ 75 10.07²751007)3 + ... +751007) similar to part @ here 75 (0.07) 7- 0.07) Pne 15/009) (1-6001)) I-0.07 as exponent of Here (0-1) comes (6.07) because are in Pn (n-1) terms only.